a) \(\dfrac{22}{55}=\dfrac{2}{5}\)

b) \(\dfrac{-63}{81}=\dfrac{-7}{9}\)

c) \(\dfrac{2.14}{7.8}=\dfrac{2.7.2}{7.2.2.2}=\dfrac{1}{2}\)

d) \(\dfrac{49+7.49}{49}=\dfrac{49.\left(7+1\right)}{49}=\dfrac{49.8}{49}=8\)

\(\dfrac{22}{55}=\dfrac{2}{5}\)                                          \(\dfrac{-63}{81}=\dfrac{-7}{9}\)

\(\dfrac{2.14}{7.8}=\dfrac{28}{56}=\dfrac{1}{2}\)                             \(\dfrac{49+7.49}{49}=8\)

a) \(\dfrac{56}{42}=\dfrac{28}{21}=\dfrac{4}{3}\)

\(\dfrac{16}{24}=\dfrac{2}{3}=\dfrac{8}{12}=\dfrac{40}{60}\)

b) \(\dfrac{40}{25}=\dfrac{8}{5}\)

\(\dfrac{63}{81}=\dfrac{7}{9}\)

\(\dfrac{36}{60}=\dfrac{3}{5}\)

mình hứa sẽ tick

= 2/5 + 1/5 + 1/5

= 4/5

b. = 2/7 + 4/7 + 5/21

= 6/21 + 12/21 + 5/21

= 23/21

HT

a, =5/14

b, = 1/6

c, = 3/2

d, = 8/7

5/14

1/6

3/2

8/7

a,5/14

b,1/6

c,3/2

d,8/7

Giải:

a) \(\dfrac{5^3.90.4^3}{25^2.3^2.2^{13}}\) 

\(=\dfrac{5^3.5.3^2.2.\left(2^2\right)^3}{\left(5^2\right)^2.3^2.2^{13}}\) 

\(=\dfrac{5^4.3^2.2.2^6}{5^4.3^2.2^{13}}\) 

\(=\dfrac{5^4.3^2.2^7}{5^4.3^2.2^{13}}\) 

\(=\dfrac{1}{2^6}=\dfrac{1}{64}\) 

b) \(\dfrac{15^2.16^4-15^3.16^3}{12^2.20^3-20^2.12^3}\) 

\(=\dfrac{15^2.16^3.16-15^2.16^3.15}{12^2.20^2.20-20^2.12^2.12}\) 

\(=\dfrac{15^2.16^3.\left(16-15\right)}{12^2.20^2.\left(20-12\right)}\) 

\(=\dfrac{\left(3.5\right)^2.\left(2^4\right)^3.1}{\left(3.2^2\right)^2.\left(2^2.5\right)^2.8}\) 

\(=\dfrac{3^2.5^2.2^{12}}{3^2.\left(2^2\right)^2.\left(2^2\right)^2.5^2.2^3}\) 

\(=\dfrac{3^2.5^2.2^{12}}{3^2.5^2.2^4.2^4.2^3}\) 

\(=\dfrac{3^2.5^2.2^{12}}{3^2.5^2.2^{11}}\) 

\(=2\) 

c) \(\dfrac{2.3+4.6+14.21}{3.5+6.10+21.35}\) 

\(=\dfrac{2.3+2.3.2.2+2.3.7.7}{3.5+3.5.2.2+3.5.7.7}\) 

\(=\dfrac{2.3+2.3.4+2.3.49}{3.5+3.5.4+3.5.49}\) 

\(=\dfrac{2.3.\left(1+4+49\right)}{3.5.\left(1+4+49\right)}\) 

\(=\dfrac{2.3}{3.5}\) 

\(=\dfrac{2}{5}\) 

Chúc bạn học tốt!

a) \(\dfrac{8}{16}=\dfrac{8:8}{16:8}=\dfrac{1}{2}\)

b) \(\dfrac{10}{30}=\dfrac{10:10}{30:10}=\dfrac{1}{3}\)

c) \(\dfrac{24}{18}=\dfrac{24:6}{18:6}=\dfrac{4}{3}\)

d) \(\dfrac{20}{28}=\dfrac{20:4}{28:4}=\dfrac{5}{7}\)

a) `(-63)/72 = (-63:9)/(72:9)=(-7)/8`

b) `20/(-140) = (20:20)/(-140:20) = 1/(-7)=(-1)/7`

c) `(3.10)/(5.24) =(3.2.5)/(5.2 .3.4)=1/4`

d) `(6.5-6.2)/(6+3)=18/9=2`

a. \(\dfrac{8,5-8,2}{16}=\dfrac{0,3}{16}=\dfrac{3}{160}\)

b. \(\dfrac{2\cdot14}{7\cdot8}=\dfrac{1\cdot2}{1\cdot4}=\dfrac{2}{4}=\dfrac{1}{2}\)

c. \(\dfrac{11\cdot4-11}{2-13}=\dfrac{11\left(4-1\right)}{-11}=\dfrac{1\cdot3}{-1}=-3\)

d. \(\dfrac{49+7\cdot49}{49}=\dfrac{49\cdot\left(1+7\right)}{49}=\dfrac{8}{1}=8\)